(4^x)-11=(3.2x)+13

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Solution for (4^x)-11=(3.2x)+13 equation: 



(4^x)-11=(3.2x)+13

We move all terms to the left:

(4^x)-11-((3.2x)+13)=0

We add all the numbers together, and all the variables

4^x-((+3.2x)+13)-11=0



We calculate terms in parentheses: -((+3.2x)+13), so:

(+3.2x)+13

We get rid of parentheses

3.2x+13

Back to the equation:

-(3.2x+13)



We get rid of parentheses

4^x-3.2x-13-11=0

We add all the numbers together, and all the variables

-3.2x+4^x-24=0

We move all terms containing x to the left, all other terms to the right

-3.2x+4^x=24

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